Java按位与与==和+的优先级比较-创新互联
文章目录
网页标题:Java按位与与==和+的优先级比较-创新互联
分享路径:http://lswzjz.com/article/dddgoj.html
- &与==
- 1.代码篇
- 2.报错提醒
- 3.改错方式
- 2.&与=
import java.util.Scanner;
public class NumberOne {public static void main(String[] args) {Scanner scanner = new Scanner(System.in);
System.out.print("Please enter a number >");
while (scanner.hasNextInt()) { int a = scanner.nextInt();
System.out.println(countOne(a));
System.out.print("Please enter a number >");
}
}
public static int countOne (int number) {int b = 1, counter = 0;
while (number != 0) { if (number & b == 1){
counter++;
}
number = number >>>1;
}
return counter;
}
}
2.报错提醒
原因是编译器先进行b==1的返回值计算在进行按位与。
import java.util.Scanner;
public class NumberOne {public static void main(String[] args) {Scanner scanner = new Scanner(System.in);
System.out.print("Please enter a number >");
while (scanner.hasNextInt()) { int a = scanner.nextInt();
System.out.println(countOne(a));
System.out.print("Please enter a number >");
}
}
public static int countOne (int number) {int b = 1, counter = 0;
while (number != 0) { if ((number & b) == 1){
counter++;
}
number = number >>>1;
}
return counter;
}
}
加上括号就可以啦!
2.&与=import java.util.Scanner;
public class OddEvenBitBinary {public static void main(String[] args) { Scanner sc = new Scanner(System.in);
System.out.print("Please enter an integer >");
while(sc.hasNextInt()) { int number = sc.nextInt();
oddEven(number);
System.out.println();
System.out.print("Please enter an integer >");
}
}
public static void oddEven(int num) {System.out.print("The odd bit of " + num + ">");
int j = 1;
int i = 0;
for (i = 30; i >= 0; i = i - 2) { System.out.print(" " + ((num >>i) & j));
}
System.out.println();
System.out.print("The even bit of " + num + ">");
for (i = 29; i >= 1; i -= 2) { System.out.print(" " + ((num >>i) & j));
}
}
}
System.out.print(" " + ((num >>i) & j)); 这一行代码的括号必须全加上,不然会出现报错!
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网页标题:Java按位与与==和+的优先级比较-创新互联
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